Y=11x^2+29x-12

Solution for Y=11x^2+29x-12 equation:

=11Y^2+29Y-12

We move all terms to the left:

-(11Y^2+29Y-12)=0

We get rid of parentheses

-11Y^2-29Y+12=0

a = -11; b = -29; c = +12;
Δ = b2-4ac
Δ = -292-4·(-11)·12
Δ = 1369
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1369}=37$
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-29)-37}{2*-11}=\frac{-8}{-22}
=4/11
$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-29)+37}{2*-11}=\frac{66}{-22}
=-3
$